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suppose that according to a health statistics survey in 1990 31% of babies and state a were born to parents who were not married throughout the 1990s this percentage increase by approximately 0.6 per year Express the percentage of babies born out of wedlock p as a function of the number of years after 1990 x

Respuesta :

In this problem we have that

p ------> percentage of babies

x -----> the number of years

so

p=0.6x+31 -------> equation that represent this situation

For a p=40%

Find the value of x

substitute the given values

40=0.6x+31

0.6x=40-31

0.6x=9

x=15 years

Find the year

1990+15=2005

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