√2 +√8=3 (2 ^1/2)
1) Solving this expression we have
[tex]\begin{gathered} \sqrt[]{2}\text{ +}\sqrt[]{8}= \\ \sqrt[]{2}\text{ +2}\sqrt[]{2} \end{gathered}[/tex]
2) Since we can rewrite this expression using the exponents like this
[tex]\begin{gathered} 2^{\frac{1}{2}}+2(2^{\frac{1}{2}})\cong4.24 \\ 3(2^{\frac{1}{2}})\cong4.24 \end{gathered}[/tex]
and since 2 raised to 1/2 works like a term, we can add. Just like we do to
x + 2x = 3x.
So the answer is √2 +√8=3 (2 ^1/2) =
√
