Respuesta :

Given the expression:

[tex]4^{x+8}=7[/tex]

Expressing this in logarithm form:

[tex]\log _47=x+8[/tex]

Next, changing base to the natural logarithm:

[tex]\begin{gathered} \frac{\ln 7}{\ln 4}=x+8 \\ \implies x=\frac{\ln7}{\ln4}-8 \end{gathered}[/tex]

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