1) Three times a number greater than 96 in algebraic notation is:
[tex]3n>96.[/tex]2) Dividing the above inequality by 3 we get:
[tex]\begin{gathered} \frac{3n}{3}>\frac{96}{3}, \\ n>32. \end{gathered}[/tex]Answer: The number we are looking for is greater than 32.
[tex]n>32.[/tex]