Answer:
[tex](\frac{1}{2},-\frac{\sqrt[]{3}}{2})[/tex]
Explanation:
The given angle:
[tex]\frac{5\pi}{3}=\frac{5\times180}{3}=300^0[/tex]
For an angle in standard position on the unit circle, the location of the terminal point will be:
[tex]\begin{gathered} (x,y)=(\cos 300^0,\sin 300^0) \\ =(\frac{1}{2},-\frac{\sqrt[]{3}}{2}) \end{gathered}[/tex]
