Note, Also, square root of m = m^1/2
This means that the expression would be
logb (x^1/2 * y)/(z^2 * w)
Recall the laws of logarithm which are expressed as
logb mn = logb m + logb n
logb m/n = logb m - logb n
logb m^n = nlog m
where b is the base
By applying these laws, we have
1/2logb x + logb y - 2logb z - logb w
= (1/2logb x + logb y) - (2logb z + logb w)
