XaelahM605697 XaelahM605697
  • 28-10-2022
  • Mathematics
contestada

Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x ≤ 93)?A. 0.975B. 0.025C. 0.84D. 0.16

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VyncentU660816 VyncentU660816
  • 28-10-2022

Answer:

A. 0.975

Explanation:

To determine P(x ≤ 93), we first find the z-score.

[tex]\begin{gathered} Z-\text{Score}=\frac{X-\mu}{\sigma} \\ =\frac{93-79}{7} \\ =\frac{14}{7} \\ =2 \end{gathered}[/tex]

Therefore:

[tex]P\begin{pmatrix}x\leqslant93\end{pmatrix}=0.975[/tex]

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