Given data:
The given time by each participant.
The mean is,
[tex]\begin{gathered} x=\frac{32+28+26+32+24+32}{6} \\ =29 \end{gathered}[/tex]The value of the mean square is,
[tex]\begin{gathered} x^2=\frac{32^2+28^2+26^2+32^2+24^2+32^2}{6} \\ =851.334 \end{gathered}[/tex]The value of the standard deviation is,
s=(851.334-(29)^2)^(1/2)
=3.21465
=3.21
Thus, the standard deviation is 3.21.
