TarajiH320734 TarajiH320734
  • 28-10-2022
  • Mathematics
contestada

A certain ore yields an average of 59% iron. How much ore is needed to obtain 826 lb of iron?

Respuesta :

ElizabethroseL264119 ElizabethroseL264119
  • 28-10-2022

First, convert 59% into decimal by dividing by 100%

[tex]59\%\div100\%=0.59[/tex]

Next, divide 826 lb by 0.59 to get the amount of ore needed

[tex]826\div0.59=1400[/tex]

Therefore, you need 1400 lb of ore to get 826 lb of iron.

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