Given the quadrilateral JKLM
x = 6, y = 3.5
We will prove the diagonals bisect each other by substitution with x, y
[tex]\begin{gathered} 2x+2=2(6)+2=14 \\ 4x-10=4(6)-10=14 \\ So,2x+2=4x-10 \\ \\ 8y-6=8(3.5)-6=22 \\ 6y+1=6(3.5)+1=22 \\ so,8y-6=6y+1 \end{gathered}[/tex]
As a result, the diagonals bisect each other
so, the quadrilateral is a parallelogram
