There are 12 months in a year and so we have
[tex]m=12t[/tex][tex]\therefore t=\frac{m}{12}[/tex][tex]V(m)=1300(0.61)^{\frac{m}{12}}[/tex]which can be written as
[tex]V(m)=1300((0.61)^{\frac{1}{12}})^m[/tex][tex]V(m)=1300(0.9596)^m[/tex]which is our answer and it is the third choice in the column.
