The area of the sector is derived as follows;
[tex]\begin{gathered} \text{Area of sector=}\frac{\theta}{360}\times\pi\times r^2 \\ \text{Area}=\frac{32}{360}\times3.14\times27.1^2 \\ \text{Area}=\frac{4\times3.14\times734.41}{45} \\ \text{Area}=\frac{9224.1896}{45} \\ \text{Area}=204.981991111\ldots \\ \text{Area}\approx205\operatorname{mm} \end{gathered}[/tex]
Please note that the final answer has been rounded off to the nearest whole number.
The answer therefore is 205 square millimeters
