Solve for x:
Take the 8th root of both sides:
[tex]\begin{gathered} \sqrt[8]{-6}=\sqrt[8]{x^8} \\ so\colon \\ x=\sqrt[8]{6(-1)} \\ x=\sqrt[8]{6}\cdot\sqrt[8]{-1} \\ Using_{\text{ }}the_{\text{ }}polar_{\text{ }}form \\ x=-\sqrt[8]{6}\cos (\frac{\pi}{8})-i\sqrt[8]{6}\sin (\frac{\pi}{8}) \end{gathered}[/tex]