Respuesta :

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where

[tex]\begin{gathered} (x-4)^2-(y-5)^2=2^2 \\ a=4 \\ b=5 \end{gathered}[/tex][tex]\begin{gathered} x^2-4x-4x+16+y^2-5y-5y+25=4 \\ x^2-8x+y^2_{}-10y+41-4=0 \end{gathered}[/tex]

Rearranging yields

[tex]x^2+y^2-8x-10y+37=0[/tex]

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