AnalisaD178791 AnalisaD178791
  • 28-10-2022
  • Mathematics
contestada

f(n) = (2n - 3)(n+1)h(t) = -8(3 – t)(h of)(1.5) =

Respuesta :

ArkinH623539 ArkinH623539
  • 28-10-2022

Answer:

(hof)(1.5) = -24

Step-by-step explanation:

We are given these following functions:

f(n) = (2n - 3)(n + 1)

h(n) = -8(3 - n)

(hof)(n) = h(f(n))

Each value of n in h is substituted by f(n).

So

h(f(n)) = h((2n - 3)(n + 1)) = -8(3 - (2n - 3)(n + 1))

When n = 1.5

h(f(1.5)) = -8(3 - (2*1.5 - 3)(1.5+1)) = -8(3 - (3-3)(2.5)) = -8(3) = -24

So

(hof)(1.5) = -24

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