Question:
Solution:
The radius of the cross-section is the adjacent side of the right triangle inside the sphere. We can find this side if we apply the Pythagoras theorem:
[tex]r\text{ = }\sqrt[]{20^2-12^2}[/tex]
this is equivalent to:
[tex]r\text{ = }\sqrt[]{20^2-12^2}\text{ = 16}[/tex]
then, the correct solution would be:
[tex]r\text{ = 16}[/tex]
