Find the equation of the line through point (8, -9) that is parallel to the line with slope -5/18

Answer
[tex]y=-\frac{5}{18}x-\frac{61}{9}[/tex]Explanation
The equation of the line can be given by the slope-intercept form:
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
Additionally, parallel lines have the same slope, meaning that if the slope of the parallel line (to our line) is -5/18, then our slope is also -5/18, leaving us with the line:
[tex]y=-\frac{5}{18}x+b[/tex]Next, we have to replace the values of the point (8, -9) given to:
[tex]-9=-\frac{5}{18}\cdot8+b[/tex][tex]-9=-\frac{20}{9}+b[/tex][tex]-9+\frac{20}{9}=b[/tex][tex]b=-9+\frac{20}{9}[/tex][tex]b=-\frac{61}{9}[/tex]Finally, by rearranging the equation we get:
[tex]y=-\frac{5}{18}x-\frac{61}{9}[/tex]