I have to find sin 0 in the following triangle. I need guidance

ANSWER:
[tex]\sin\theta=\frac{4\sqrt{13}}{17}[/tex]STEP-BY-STEP EXPLANATION:
The sine is the ratio between the leg opposite the angle and the hypotenuse.
The leg opposite the angle shown in the image is 4√ 13.
Therefore:
[tex]\sin\theta=\frac{4\sqrt{13}}{17}[/tex]