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Given: CF bisects AD.47°B479DFWhich triangle congruence theorem or postulatecould be used to prove AABC = ADBF?O Angle-Side-Angle (ASA)Side-Side-Side (SSS)Side-Angle-Side (SAS)Angle-Angle-Side (AAS)

Given CF bisects AD47B479DFWhich triangle congruence theorem or postulatecould be used to prove AABC ADBFO AngleSideAngle ASASideSideSide SSSSideAngleSide SASAn class=
Given CF bisects AD47B479DFWhich triangle congruence theorem or postulatecould be used to prove AABC ADBFO AngleSideAngle ASASideSideSide SSSSideAngleSide SASAn class=

Respuesta :

1) First, from the picture we see that we have two equal angles: ∠A = ∠D = 47°.

2) Secondly, We also know that the line CF bisects AD.

3) Finally, the two opposite angles of B are equal, we call these angles ∠B.

From (1)-(2)-(3) we conclude that the answer is: angle-side-angle (ASA).

For example, we have the side/line AB between angles ∠A and ∠B.

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