From the problem, we have :
[tex]x^2<16[/tex]
Note that if the inequality symbol is <, the solution is is the form :
[tex]awhere b is greater than a.
Solve for x :
[tex]\begin{gathered} x^2<16 \\ \sqrt[]{x^2}<\sqrt[]{16} \\ x<\pm4 \end{gathered}[/tex]
So we have two values of x, -4 and 4. Using the format above, 4 is greater than -4.
The solution will be :
[tex]-4Note also that if the inequality symbol is < or >, the endpoints are
open circles.Graph the solution :
