The direction of a vector is given as:
[tex]\theta=\tan ^{-1}(\frac{v_y}{v_x})[/tex]
where vx and vy are the components along the axis.
Plugging the values given we have:
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{9}{12}) \\ \theta=36.87 \end{gathered}[/tex]
Therefore the direction of the vector is 36.87°
