Since we have that the volume of a sphere is given by:
[tex]V=\frac{3}{4}\pi r^3[/tex]
And we have that the diameter equals 3.6ft, we then will have a volume of:
[tex]V=\frac{3}{4}\pi(1.8)^3\Rightarrow V\approx13.74[/tex]
Since we have that the volume is approximately 13.74 ft^3, then the best approximation in the problem is A. 13.6 ft^3.
