The current is defined as:
[tex]I=\frac{Q}{t}[/tex]Plugging the values given and solving for t we have that:
[tex]\begin{gathered} 5\times10^{-3}=\frac{2}{t} \\ t=\frac{2}{5\times10^{-3}} \\ t=400 \end{gathered}[/tex]Therefore it will take 400 seconds.
