Respuesta :

So given that -1 is a zero, we can say that a factor of the polynomial is x+1.

Then,

[tex]\begin{gathered} h(x)=x^3+x^2-9x-9 \\ h(x)=x^2(x+1)-9(x+1) \\ h(x)=(x+1)(x^2-9) \\ h(x)=(x+1)(x+3)(x-3) \end{gathered}[/tex]

Therefore,

h(x) = (x+1)(x+3)(x-3)

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