Given:
the terminal side θ passes through the point (8,-7)
so,
[tex](x,y)=(8,-7)[/tex]The point lying in quarter number 4
so,
[tex]\begin{gathered} \tan \theta=\frac{y}{x}=-\frac{7}{8} \\ \\ \theta=\tan ^{-1}(-\frac{7}{8})=-41.186 \\ \\ \theta=360-41.186=318.814 \end{gathered}[/tex]
