Solution:
Given;
[tex]w=l+10,P=140ft[/tex]The perimeter of a rectangle is;
[tex]\begin{gathered} P=2(l+w) \\ \\ 140=2(l+l+10) \\ \\ \frac{140}{2}=2l+10 \\ \\ 70-10=2l \\ \\ 2l=60 \\ \\ l=\frac{60}{2} \\ \\ l=30ft \end{gathered}[/tex]Then;
[tex]\begin{gathered} w=30+10 \\ \\ w=40ft \end{gathered}[/tex]CORRECT ANSWER:
[tex]\begin{gathered} Width=40ft \\ \\ Length=30ft \end{gathered}[/tex]