LadarionQ541660 LadarionQ541660
  • 28-10-2022
  • Mathematics
contestada

hi! i need help please, thanks! (#4) (EXTRA CREDIT ASSIGNMENT)

hi i need help please thanks 4 EXTRA CREDIT ASSIGNMENT class=

Respuesta :

ArnezM257429 ArnezM257429
  • 28-10-2022

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

graph:

point 1 (-8, 3) x1 = -8 y1 = 3

point 2 (0, -5) x2 = 0 y2 = -5

Step 02:

equation of the line:

slope:

[tex]\text{slope = }\frac{y2-y1}{x2-x1}=\frac{-5-3}{0-(-8)}=\frac{-8}{8}=-1[/tex]

(y - y1) = m (x - x1)

(y - 3) = -1 (x - (-8))

y - 3 = -x - 8

y = -x - 8 + 3

y = -x - 5

The answer is:

y = -x - 5

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