Given:
The lines AB and CD intersect at point 0.
The lines C A and BD are parallel.
Required:
To prove that ACO ~BD0.
Explanation:
It is given that AB and CD intersect at point O.
Therefore,
[tex]\angle AOC=\angle BOC[/tex]
And CA and BD are parallel.
So, alternate opposite angles are equal.
Therefore,
[tex]\begin{gathered} \angle OCA=\angle OBD \\ \angle OAC=\angle ODB \end{gathered}[/tex]
The all three angles are same, and CA is parallel to BD.
Therefore, ACO ~BD0.
Final Answer:
ACO ~BD0.
