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A piston cylinder holds a 3.00 L volume of air at 300.0 K.The cylinder holds the gas at 3.25 atm pressure.How many moles of air are present in the cylinder under these conditions?0.3640.4830.3960.443

Respuesta :

In this question, we have a situation in which we have to use the Ideal gas law formula in order to find the missing number of moles of this gas, the formula is the following:

PV = nRT

We have:

P = 3.25 atm

V = 3.00 L

n = number of moles we don't have yet

R = gas constant value, 0.082

T = 300 K

Now we add these values into the formula:

3.25 * 3 = n * 0.082 * 300

9.75 = 24.6n

n = 0.396 moles of air, letter C