Given:
[tex]y-1=-3(x+2)[/tex]
Required:
To convert the given equation into slope-Intercept form.
Explanation:
Consider the given equation,
[tex]y-1=-3(x+2)[/tex]
We know that, the slope-Intercept form is represented as
[tex]y=mx+b[/tex]
Here, we have to write the given equation in this form.
For this
[tex]\begin{gathered} y-1=-3(x+2) \\ y-1=-3x-6 \\ y=-3x-6+1 \\ y=-3x-5 \end{gathered}[/tex]
Final Answer:
The slope-Intercept form of the given equation is
[tex]y=-3x-5[/tex]
