Respuesta :

let x be the length of PR. Let y be the length of QR.

we get that the length of PQ is:

[tex]z=\sqrt[]{x^2+y^2}[/tex]

so we get that:

[tex]\sin P=\frac{y}{z},\cos Q=\frac{y}{z},\tan P=\frac{y}{x},\tan Q=\frac{x}{y}[/tex]