Given that triangles ABC and XYZ are similar
Step 1 : State the theorem for similar triangles
Side-Side-Side
Thus
[tex]\begin{gathered} AC\cong XZ \\ AB\cong XY \\ BC\cong YZ \end{gathered}[/tex]Step 2: define the sine of the acute angle in the two triangles
[tex]\begin{gathered} In\text{ triangle ABC} \\ \sin \theta=\frac{BC}{AC}=\frac{1}{2} \\ \text{From similarity of the sides} \\ In\text{ triangle XYZ} \\ \sin \theta=\frac{YZ}{ZX}=\frac{1}{2} \end{gathered}[/tex]The answer is 1/2
