The surface area of a cone is given by
[tex]A=\pi Lr+r^2\pi[/tex]
Where 'r' denotes the radius of the base, and 'L' the slant height of the cone. In our cone, we have the following measures:
[tex]\begin{cases}r=2in \\ L=12in\end{cases}[/tex]
Plugging those values in our formula, we get the following:
[tex]A=\pi\times12\times2+(2)^2\pi=24\pi+4\pi=28\pi\approx88in^2[/tex]
And this is our answer. The surface area is 88in².
