Respuesta :

Given:

[tex]\frac{14x^2-12x}{x+6}[/tex]

To find the zeros:

Let the numerator be equal to zero

[tex]\begin{gathered} 14x^2-12x=0 \\ 2x\mleft(7x-6\mright)=0 \\ x=0,\frac{6}{7} \end{gathered}[/tex]

Hence, the zeros are,

[tex](\frac{6}{7},0),(0,0)[/tex]

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