XariaN754585 XariaN754585
  • 26-10-2022
  • Mathematics
contestada

[tex]9 {}^{ - 3} [/tex]equivalent to 1/9

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AntwannO73958 AntwannO73958
  • 26-10-2022

A negative exponent in the numerator is equivalent to the same exponent but positive in the denominator.

Then, we have:

[tex]9^{-1}=\frac{1}{9^1}=\frac{1}{9}[/tex]

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