MalenieR511723 MalenieR511723

26-10-2022
Mathematics

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if k=3, evaluate the following function [7(k+6)]/(k to the second power) +k to the 3 power)

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JuanmiguelZ382407 JuanmiguelZ382407

26-10-2022

[tex]\frac{7(k+6)}{k^2}+k^3[/tex]

With k = 3

[tex]\frac{7(3+6)}{3^2^{}}+3^3=\frac{7\cdot9}{9^{}}+27=\frac{63}{9}+27=7+27=34[/tex]

The answer is 34

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