[tex]\begin{gathered} x=\sqrt[]{2t} \\ y=2t-3 \end{gathered}[/tex]
From the first equation, we have:
[tex]t=\frac{x^2}{2}[/tex]
Here, we must take in consideration that x can't be negative, sinte we derive this relation from a square root function.
Replacing t with this result in the parametric function for y, we have:
[tex]\begin{gathered} y=2\frac{x^2}{2}-3 \\ y=x^2-3 \end{gathered}[/tex]
Answer:
Option A: The rectangular equation is y = x²-3 with the restriction x>=0
