From the diagram above
Opp = 10
Hyp = 15
Angle = x
[tex]\begin{gathered} By\text{ using the trigonometry formular we have.} \\ \sin \theta\text{ =}\frac{\text{Opp}}{\text{Adj}} \\ \sin \text{ x =}\frac{10}{15} \\ \sin \text{ x = 0.666} \\ x=sin^{-1}(\text{0.666}) \\ x\text{ = 41.8}\approx\text{ 42} \\ \end{gathered}[/tex]
