Given data
*The given Young's Modulus is
[tex]Y=1.3\times10^{10}N/m^2[/tex]
*The given speed is v = 280 m/s
The formula for the density of iron is given as
[tex]\begin{gathered} v=\sqrt[]{\frac{Y}{D}} \\ D=\frac{Y}{v^2} \end{gathered}[/tex]
Substitute the known values in the above expression as
[tex]\begin{gathered} D=\frac{(1.3\times10^{10})}{(280)^2} \\ =1.65\times10^5 \end{gathered}[/tex]
