Solution
For this case we have the following function:
[tex]y=(x+2)^2+6[/tex]We can expand the terms and we have:
y= x^2 +4x+4 +6 = x^2 +4x+10
And then we can find the equation for the axis of symettry with:
[tex]y=-\frac{b}{2a}[/tex]a= 1, b= 4 then
[tex]y=-\frac{4}{2\cdot1}=-2[/tex]Then the answer for this case is:
y= -2
