Respuesta :

Given that BE is diameter and CD is perpendicular, we can deduct that arcs CE and DE are equal.

[tex]\begin{gathered} arc(CD)=arc(CE)+arc(DE) \\ 90=2\cdot arc(CE) \\ \text{arc(CE)}=45=arc(DE) \end{gathered}[/tex]

Therefore, arc DE is 45°.