KalixB396241 KalixB396241

26-10-2022
Chemistry

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How many milliliters of 10.5 M HCl(aq) are needed to prepare 795.0 mL of 1.00 M HCl(aq)?

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EllaniQ236824 EllaniQ236824

26-10-2022

To solve this we use this formula

M1 x V1 = M2 x V2

1 is for solution number 1

2 is for solution 2

Now, we need to clear V1

So, M1 x V1 = M2 x V2

V1 = M2 x V2 / M1 = 1.00 M x 795.0 mL / 10.5 M = 75.71 mL

Answer: V1 = 75.71 mL

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