2/9 lb -------------------------->3 bags
1 lb ------------------------------>x bags
Using cross-multiplication:
[tex]\begin{gathered} \frac{\frac{2}{9}}{1}=\frac{3}{x} \\ \frac{2}{9}=\frac{3}{x} \end{gathered}[/tex]Solve for x:
[tex]\begin{gathered} x=\frac{9\cdot3}{2} \\ x=\frac{27}{2} \\ x=13.5 \end{gathered}[/tex]Answer:
13.5 bags
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Let:
x = Number of bags needed
Multiplication:
[tex]x=\frac{9}{2}\times3[/tex]Division:
[tex]x=27\div2[/tex]