Given:
The equation is
[tex]4X^2+32X-28=0[/tex]Required:
Determine which equation has the same solutions as the equation below.
Explanation:
We have
[tex]\begin{gathered} 4X^2+32X-28=0 \\ \text{ We can write it as} \\ X^2+8X-7=0 \\ X^2+2\times4\times X-7+16=16 \\ X^2+2\times4\times X+16=23 \\ (X+4)^2=23 \end{gathered}[/tex]Answer:
Option A is correct.
