MayerlinZ531881 MayerlinZ531881

26-10-2022
Mathematics

contestada

g(t)=(t+1)^2-20.25what is the vertex of the parabola? (_,_)

Respuesta :

TayonaO713896 TayonaO713896

26-10-2022

[tex]\begin{gathered} (t+1)^2-20.25=0 \\ (t+1)^2-20.25=0 \\ t^2+t+1-2.25=0 \\ t^2+t-19.25=0 \end{gathered}[/tex]

Solving for t,

[tex]\frac{-1\pm\sqrt[]{1+4\times19.25}}{2}=\frac{-1\pm8.8}{2}=3.5;-5.5[/tex]

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