The limit of a removable discontinuity is simply the value the function would take at that discontinuity if it were not a discontinuity.
We are told to solve the function below
[tex]\lim _{x\to6^+}f(x)[/tex]
Hence, from the graph
[tex]x\rightarrow6^+,\text{ the value of f(x) = 5}[/tex]
Therefore,
[tex]\lim _{x\to6^+}f(x)=5[/tex]
The answer is Option C.
