zhijing0634 zhijing0634
  • 31-07-2022
  • Mathematics
contestada

Cos3A ×cos2A =cos A ×cos 2A -sin4A×sin A=prove it

Respuesta :

surjithayer surjithayer
  • 06-08-2022

Answer:

Step-by-step explanation:

cosA×cos 2A-sin4A×sinA

=cosAcos2A-2sin2Acos2A sin A

=cos 2A(cosA-2sin2AsinA)

=cos 2A(cosA-2×2sinAcosAsin A)

=cos2A×cosA(1-4sin²A)

=cos 2AcosA(1-4(1-cos²A))

=cos2A×cosA(1-4+4cos²A)

=cos 2A(-3cosA+4cos³A)

=cos 2A(4cos³A-3cosA)

=cos 2A×cos3A

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