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28-07-2022
Chemistry

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What is the [OH-] if the [H3O+] is 1 x 10 -6?

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Аноним Аноним

28-07-2022

The answer is [OH⁻] = 1 x 10⁻⁸.

To find OH⁻, divide the ionic product of water by [H₃O⁺] as :

OH⁻ + H₃O⁺ = H₂O

[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
[OH⁻] = 1 x 10⁻⁸

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