davidspencerdavis101
davidspencerdavis101 davidspencerdavis101
  • 26-07-2022
  • Mathematics
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[tex]\int_{1}^{7} \frac{1}{x^{8}} d x[/tex]
\int_{1}^{7} \frac{1}{x^{8}} d x​

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LammettHash
LammettHash LammettHash
  • 26-07-2022

Use the power rule,

[tex]\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C[/tex]

with [tex]n=-8[/tex]. It follows by the fundamental theorem of calculus that

[tex]\displaystyle \int_1^7 \frac{dx}{x^8} = -\frac1{7x^7} \bigg|_{x=1}^{x=7} = -\frac17 \left(\frac1{7^7} - \frac1{1^7}\right) = \boxed{\frac17 - \frac1{7^8}}[/tex]

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