In the imaged attached, the most precise name for ABCD Â is known to be rhombus.
What is the shape about?
Looking at the shape attached, one can see that the diagonals of a parallelogram are said to be bisecting one other and if it cross at right angles, it is said to be a rhombus.
Using the Diagonal midpoints of AC and BD, the equation will be:
(A+C)/2
(B+D)/2
To find if the midpoints are similar, then:
A +C = (3, 5) +(6, 2) = (9, 7)
B +D = (7, 6) +(2, 1) = (9, 7)
Therefore, from the solution above, the midpoints of the diagonals are the same, making the shape to be a parallelogram.
In terms of Diagonal vectors, the shape will be perpendicular when the figure is a rhombus. So:
 AC = C -A = (6, 2) -(3, 5) = (3, -3)
BD = D -B = (2, 1) -(7, 6) = (-5, -5)
So the lengths will be (3√2 vs 5√2).
Note also that the dot-product of these values need to be zero if they are perpendicular and as such:
 AC·BD = x1·x2 +y1·y2 = (3)(-5) +(-3)(-5) = -15 +15 = 0
Therefore, one can say that the diagonals are known to different length and are perpendicular bisectors, so the shape above is regarded as rhombus.
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